一道数学题,计算题 如下图所示

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 15:57:29
一道数学题,计算题 如下图所示
xQ[k@+BҘI&WIB\ɵnlV "" 雫b>L6PX0sdW_χWlݠ<|<9zV;>>;Z[wX݁|'p;`]E(&i{ix$ >zk5 cnd^{&1Bfcga!0c;RclbKE1B߲mƊ`+V{;cQhzh(:ˀ(uLt! $h+fa eΪݷTTDBAeSEY(O%ެ2.r j$Yƴ_.3R´a',!/\ ^b񯬦hse*n.5tv5mcoe~8˟n6b>>(` ^|kĭxBSCP"@41Uz^a .b=02,q&QY]dA0q&

一道数学题,计算题 如下图所示
一道数学题,计算题 如下图所示

一道数学题,计算题 如下图所示
(x√x+x√y)/(xy-y^2)-(x+√xy+y)/(x√x-y√y)
=x(√x+√y)/y(x-y)-(x+√xy+y)(x√x+y√y)/(x√x-y√y)(x√x+y√y)
=x(√x+√y)/y(x-y)-(x^2+xy+y^2)(√x+√y)/(x^3-y^3)
=x(√x+√y)/y(x-y)-(x^2+xy+y^2)(√x+√y)/(x-y)(x^2+xy+y^2)
=x(√x+√y)/y(x-y)-(√x+√y)/(x-y)
=[x(√x+√y)-y(√x+√y)]/y(x-y)
=(x-y)(√x+√y)/y(x-y)
=(√x+√y)/y
这已经是最简形式了

设 原式= ① - ②
① = x(√x-√y) / (y(x-y)) = ( x / y) * (1/(√x-√y) )
② = (x+√x *√y +y) / ( (√x)^3 - (√y)^3) = 1/(√x-√y)
原式= (x/y-1) * 1/(√x-√y)
= (√x +√y) / y