lim x [sin ln(1+3/x)-sin ln(1+1/x)],x趋近于无穷大,

lim x [sin ln(1+3/x)-sin ln(1+1/x)],x趋近于无穷大, 求极限lim[sin(x^3)/x(x-ln(1+sinx))] x趋于0lim[sin(x^3)/x(x-ln(1+sinx))] x趋于0 lim(x趋向0)ln(1+sin x)/x^2 lim (x^x-sin(x)^x)/(sin(x)sin(x)ln(1+tan(x))) x趋于零 求解当x趋向0时lim[sin(2^x)ln(x+1)]/(2^x-1) lim(x->0）［ln（1+3x）］/sin（2x）求过程 求极限ln(1+2x)/sin(1+2x),lim x->0求它极限. 求极限lim(x趋向于0)ln(1+x^2)/sin(1+x^2) 求极限：lim x→0 ln[1+sin^2(x)]/[e^(x^2)－1] lim(x→0)[ln(1+x^2)]/[sin(1+x^2)] 求lim(x→0)(sin(ln(1+x)/x-1)/sinx 求极限 ln (1+2x)/sin x,lim x->0 请用洛必达法则求解, 求极限lim┬(x→0)⁡〖(tan⁡x-sin⁡x)/ln⁡(1+x^3 ) 〗lim┬(x→0)⁡〖(x-sin⁡x)/x^3 〗 lim[sin(ln x)-sin(ln sinx)],x趋近于0+ lim*[ln(1+3X)]/sin4X {X->0}求极限lim*[ln(1+3X)]/sin4X {X->0} 求极限 求Lim(x->∞)[ln(1+3*x^2)]/[ln(3+x^4)]的 极限 求极限 ln x/ ln (sin x),lim x->0 请用洛必达法则求解, lim[ln(1+x)+ln(1-x)]/(tanx)^2