b=log2根号3,c=log3根号2怎么比较大小?

b=log2根号3,c=log3根号2怎么比较大小? 设a=log3π,b=log2根号3,c=log3根号2则它们之间的大小关系 设a=log3π,b=log2根号3,c=log3根号2,则a,b,c,的大小关系为 b=log2根号3=1/2[log2(3)]=1/2[1/log3(2)]=1/log3(4) log2^25*log3^2倍根号2*log5^9= log2^5*log3^2倍根号2*log5^9= (log3^4+log5^2)(log2^9+log2^根号3) 幂函数如何比较大小?例题：设Y=log3圆周率,b=log2根号三,c=log3根号2,则a,b,c的大小关系是? 已知a=log2为底3的对数+log2为底根号3的对数,b=log2为底9的对数-log2为底根号3的对数,c=log3为底2的对数则a,b,c的大小关系为 a=(3/4)^0.5 b=(4/3)^0.4 c=log3/4^(log3^4)则abc的大小还有一题,函数y=根号下log2^x-2^-x的定义域 log2(3)+log3(5)+log3(2)=? (log2 6)×(log3 6)-(log2 3+log3 2)= (log2 6)×(log3 6)-(log2 3+log3 2)= log2(3)*log3(2)=? (log3^2)(log2^3)= (log2 5+log4 125)log3 2/ log根号3 5 log3(2)=a,3^b=5,用a,b表示log3(根号30) log2(1+根号2+根号3）+log2（1+根号2-根号3）= 1、计算log5^35+2log1/2^根号2-log5^1/50-log5^14 2、已知log3^7=a,log2^3=b,求log21^28