作业帮sin(65°-x)cos(x-20°)+cos(65°-x)cos(110°-x)=?
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sin(65°-x)cos(x-20°)+cos(65°-x)cos(110°-x)=?
sin(65°-x)cos(x-20°)+cos(65°-x)cos(110°-x)=?
sin(65°-x)cos(x-20°)+cos(65°-x)cos(110°-x)=?
sin(65°-x)cos(x-20°)+cos(65°-x)cos(110°-x)
＝sin(65°-x)cos(x-20°)+cos(65°-x)sin(x-20°)
=sin45°
=√2/2
cos(x-20°)用sin。。。表示
因为cos(110°-x)=cos(20°+90°-x)=-sin(20°-x)=sin(x-20°)
所以sin(65°-x)cos(x-20°)+cos(65°-x)cos(110°-x)=sin(65°-x)cos(x-20°)+cos(65°-x)sin(x-20°)=sin(65°-x+x-20°)=sin45°=ㄏ2/2
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