作业帮[(-1+根号3i)^3]/[(1+i)^6]+[-2+i]/[1+2i]的值是
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[(-1+根号3i)^3]/[(1+i)^6]+[-2+i]/[1+2i]的值是
[(-1+根号3i)^3]/[(1+i)^6]+[-2+i]/[1+2i]的值是
[(-1+根号3i)^3]/[(1+i)^6]+[-2+i]/[1+2i]的值是
[(-1+根号3i)^3]/[(1+i)^6]+[-2+i]/[1+2i]
=[(-1+根号3i)³]/(2i)³ + [(-2+i)(1-2i)]/[(1+2i)(1-2i)]
=[(-1+根号3i)/(2i)]³ + (5i)/5
=[根号3/2 - (1/2)*i]³+ i
=[cos(-π/6)+ i*sin(-π/6)]³+ i
=cos(-π/2)+ i*sin(-π/2)+ i
=-i+i
=0
I根号2-1I+Iπ-3I-I3.14-πI-根号2
计算i(1-根号3i
(1-根号3i)/(根号3+i)^2 求详解!
复数(1+根号3i)/(根号3-i)=?
复数(根号3 -i)/(1+根号3i)=
(1+根号3i)^2/根号3-i=
根号3+i/（1-根号3i）*2
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